Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
If the speed of sound in air is 330 m / s, then find the number of tones present in an open organ pipe of length 1 m whose frequency is ≤ 1000 Hz.
Q. If the speed of sound in air is
330
m
/
s
, then find the number of tones present in an open organ pipe of length
1
m
whose frequency is
≤
1000
Hz
.
686
166
Waves
Report Error
A
2
B
4
C
8
D
6
Solution:
Given, speed of sound in air,
v
=
330
m
/
s
Length of organ pipe,
L
=
1
m
and frequency,
v
=
1000
Hz
For an open organ pipe,
Fundamental frequency,
v
1
=
2
L
v
=
2
×
1
330
=
165
Hz
∴
Number of tones present in the open organ pipe
=
v
1
v
=
165
1000
=
6.06
≃
6