Question

If the set $x$ contains $7$ elements and set $y$ contains 8 elements, then the number of bijections from $x$ to $y$ is

• A. $0$
• B. $7!$
• C. $8P_7$
• D. $8!$

Answer 1

Answer: (A)

$n(A)\ne n(B)$
Number of bijections is zero