If the resultant of two unlike parallel forces of magnitudes 10 N and 16 N act along a line at a distance of 24 cm from the line of action of the smaller force is 8 N, then the distance between the lines of action of the force is:

Question

If the resultant of two unlike parallel forces of magnitudes 10 N and 16 N act along a line at a distance of 24 cm from the line of action of the smaller force is 8 N, then the distance between the lines of action of the force is: (A) 12 cm (B) 8 cm (C) 10.66 cm (D) 18 cm

Tardigrade Admin · Accepted Answer

Let the forces of magnitudes 10 N and 16 N be acting at A and B respectively. Suppose the resultant acts at C. Then <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/1f417146674f0414f0fc29e6411fb0a2-.png" /> Taking moment of forces about B. 10.x=8.(24-x) ⇒ 10x=192-8x ⇒ 18x=192 ⇒ x=10.66 cm

Q. If the resultant of two unlike parallel forces of magnitudes $10 N$ and $16 N$ act along a line at a distance of $24 c m$ from the line of action of the smaller force is $8 N$ , then the distance between the lines of action of the force is:

12 cm

8 cm

10.66 cm

18 cm

Let the forces of magnitudes $10 N$ and $16 N$ be acting at A and B respectively. Suppose the resultant acts at C. Then

Taking moment of forces about B.
$10. x = 8. (24 - x)$
$\Rightarrow$ $10 x = 192 - 8 x$
$\Rightarrow$ $18 x = 192$
$\Rightarrow$ $x = 10.66 c m$

Q. If the resultant of two unlike parallel forces of magnitudes 10N and 16N act along a line at a distance of 24cm from the line of action of the smaller force is 8N, then the distance between the lines of action of the force is: