Question

If the resonance energy of C-H bond is 24.3 kJ/mol the electronegativity difference of C and H is

• A. 1.02
• B. 0.50
• C. 0.80
• D. 1.04

Answer 1

Answer: (B)

Electronegativity difference $=0.101\sqrt{{\Delta }_{AB}}$
where ${\Delta }_{AB}$ in kJ/mol
$=0.101\sqrt{24.3}=0.5$