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Q. If the resonance energy of C-H bond is 24.3 kJ/mol the electronegativity difference of C and H is

Classification of Elements and Periodicity in Properties

Solution:

Electronegativity difference $=0.101 \sqrt{\Delta_{A B}}$
where $\Delta_{AB}$ in kJ/mol
$=0.101 \sqrt{24.3}=0.5$