Question

If the product of the roots of the equation $x^2-3x+k+5=0$ is 7 , then the roots are real for $k=$

• A. 2
• B. 3
• C. $-2$
• D. $\varphi$

Answer 1

Answer: (D)

$x^2-3x+k+5=0$
$\because$ Product of the roots $=7$
$\Rightarrow k+5=7$
$\therefore k=2$.
Now for $k=2$, disc $<0\Rightarrow$ no real roots