Question

If the product of the roots of the equation $m{x}^2+6x+(2m-1)=0$ is -1, then the value of $m$ is

• A. $1$
• B. $-1$
• C. $\frac{1}{3}$
• D. $-\frac{1}{3}$

Answer 1

Answer: (C)

Product of the roots = $\frac{2m-1}{m}=-1$
$\Rightarrow 2m-1=-m$
$\Rightarrow 3m=1$
$\Rightarrow m=\frac{1}{3}$