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  4. If the product of the roots of the equation mx2 + 6x + (2m - 1) = 0 is -1, then the value of m is

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Q. If the product of the roots of the equation $mx^2 + 6x + (2m - 1) = 0$ is -1, then the value of $m$ is

Complex Numbers and Quadratic Equations

Solution:

Product of the roots = $\frac{2m -1}{m} = - 1$
$\Rightarrow \, 2m - 1 = - m \,$
$\Rightarrow 3m = 1$
$\Rightarrow \,m = \frac{1}{3}$