Question

If the product of roots of the equation $m{x}^2+6x+(2m-1)=0$ is $-1$, then the value of $m$ is

• A. 1/3
• B. 1
• C. 3
• D. -1
• E. -3

Answer 1

Answer: (A)

We have,
$m{x}^2+6x+(2m-1)=0$
$\therefore$ Product of roots $=\frac{2m-1}{m}$
$\Rightarrow \frac{2m-1}{m}=-1[\because$ product of roots $=-1]$
$\Rightarrow 2m-1=-m$
$\Rightarrow 3m=1$
$\Rightarrow m=\frac{1}{3}$