Question

If the product of roots of the equation $mx^2 + 6x + (2m - 1) = 0$ is $-1$, then the value of $m$ is

• A. 1/3
• B. 1
• C. 3
• D. -1
• E. -3

Answer 1

Answer: (A)

We have,
$m x^{2}+6 x+(2\, m-1) =0$
$\therefore $ Product of roots $=\frac{2 m-1}{m}$
$\Rightarrow \frac{2 \,m-1}{m}=-1 \,[\because$ product of roots $=-1]$
$\Rightarrow 2 \,m-1=-m$
$\Rightarrow 3 \,m=1$
$\Rightarrow m=\frac{1}{3}$