If the potential difference applied to an X-ray tube is 5 kV and the current through it is 6.4 mA, then number of electrons striking the target per second is y × 1016. Find y.

Question

If the potential difference applied to an X-ray tube is 5 kV and the current through it is 6.4 mA, then number of electrons striking the target per second is y × 1016. Find y. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

n e=I n × 1.6 × 10-19=6.4 × 10-3 ⇒ n=4 × 1016 / s

Q. If the potential difference applied to an $X$ -ray tube is $5 kV$ and the current through it is $6.4 m A$ , then number of electrons striking the target per second is $y \times 1 0^{16}$ . Find $y$ .

$n e = I$
$n \times 1.6 \times 1 0^{- 19} = 6.4 \times 1 0^{- 3}$
$\Rightarrow n = 4 \times 1 0^{16} / s$

Q. If the potential difference applied to an X-ray tube is 5kV and the current through it is 6.4mA, then number of electrons striking the target per second is y×1016. Find y.

ne=I n×1.6×10−19=6.4×10−3 ⇒n=4×1016/s

Q. If the potential difference applied to an $X$ -ray tube is $5 kV$ and the current through it is $6.4 m A$ , then number of electrons striking the target per second is $y \times 1 0^{16}$ . Find $y$ .

$n e = I$
$n \times 1.6 \times 1 0^{- 19} = 6.4 \times 1 0^{- 3}$
$\Rightarrow n = 4 \times 1 0^{16} / s$