If the position vectors of the vertices A , B , C of triangle ABC are (1,1,1),(2,3,4),(-2,0,3) respectively, then the magnitude of the vector representing the internal bisector of angle BAC, is

Question

If the position vectors of the vertices A , B , C of triangle ABC are (1,1,1),(2,3,4),(-2,0,3) respectively, then the magnitude of the vector representing the internal bisector of angle BAC, is (A) (√27/2) (B) (√30/2) (C) (√35/2) (D) (√33/2)

Tardigrade Admin · Accepted Answer

| AM |=√1+(1/4)+(25/4)=(√30/2)

Q. If the position vectors of the vertices $A, B, C$ of triangle $A BC$ are $(1, 1, 1), (2, 3, 4), (- 2, 0, 3)$ respectively, then the magnitude of the vector representing the internal bisector of $∠ B A C$ , is

$\frac{27}{2}$

$\frac{30}{2}$

$\frac{35}{2}$

$\frac{33}{2}$

$∣ A M ∣ = 1 + \frac{1}{4} + \frac{25}{4} = \frac{30}{2}$

Q. If the position vectors of the vertices A,B,C of triangle ABC are (1,1,1),(2,3,4),(−2,0,3) respectively, then the magnitude of the vector representing the internal bisector of ∠BAC, is

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