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  4. If the position vectors of the vertices A , B , C of triangle ABC are (1,1,1),(2,3,4),(-2,0,3) respectively, then the magnitude of the vector representing the internal bisector of angle BAC, is

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Q. If the position vectors of the vertices $A , B , C$ of triangle $ABC$ are $(1,1,1),(2,3,4),(-2,0,3)$ respectively, then the magnitude of the vector representing the internal bisector of $\angle BAC$, is

Vector Algebra

Solution:

$|\overrightarrow{ AM }|=\sqrt{1+\frac{1}{4}+\frac{25}{4}}=\frac{\sqrt{30}}{2}$

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