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Question
Mathematics
If the number of terms in the expansion of (x+y+z)n are 36, then the value of n is
Q. If the number of terms in the expansion of
(
x
+
y
+
z
)
n
are
36
, then the value of
n
is
2274
249
Binomial Theorem
Report Error
A
6
B
7
C
8
D
9
Solution:
Number of terms in the expansion of
(
x
+
y
+
z
)
n
is
(
n
+
1
)
(
n
+
2
)
/2
=
36
or
(
n
+
1
)
(
n
+
2
)
=
72
or
n
=
7