If the nuclear radius of 27 Al is 3.6 Fermi, the approximate nuclear radius of 64 Cu in Fermi is

Question

If the nuclear radius of 27 Al is 3.6 Fermi, the approximate nuclear radius of 64 Cu in Fermi is (A) 2.4 (B) 1.2 (C) 4.8 (D) 3.6

Tardigrade Admin · Accepted Answer

Nuclear radius r propto A1 / 3, where A is mass number r =r0 A1 / 3=r0(27)1 / 3=3 r0 r0 =(3.6/3)=1.2 fm For 64 Cu , r=r0 A1 / 3=1.2 fm (64)1 / 3 =4.8 fm

Q. If the nuclear radius of $^{27} A l$ is $3.6$ Fermi, the approximate nuclear radius of $^{64} C u$ in Fermi is

2.4

1.2

4.8

3.6

Nuclear radius $r \propto A^{1/3}$ , where $A$ is mass number
$r = r_{0} A^{1/3} = r_{0} (27)^{1/3} = 3 r_{0}$
$r_{0} = \frac{3.6}{3} = 1.2 f m$
For $^{64} C u, r = r_{0} A^{1/3} = 1.2 f m (64)^{1/3}$
$= 4.8 f m$

Q. If the nuclear radius of 27Al is 3.6 Fermi, the approximate nuclear radius of 64Cu in Fermi is

2.4

1.2

4.8

3.6

Nuclear radius r∝A1/3, where A is mass number r=r0​A1/3=r0​(27)1/3=3r0​ r0​=33.6​=1.2fm For 64Cu,r=r0​A1/3=1.2fm(64)1/3 =4.8fm

Q. If the nuclear radius of $^{27} A l$ is $3.6$ Fermi, the approximate nuclear radius of $^{64} C u$ in Fermi is

Nuclear radius $r \propto A^{1/3}$ , where $A$ is mass number
$r = r_{0} A^{1/3} = r_{0} (27)^{1/3} = 3 r_{0}$
$r_{0} = \frac{3.6}{3} = 1.2 f m$
For $^{64} C u, r = r_{0} A^{1/3} = 1.2 f m (64)^{1/3}$
$= 4.8 f m$