If the nuclear radius of 27 AI is 3.6 fermi, the approximate nuclear radius of 64Cu in fermi is

Question

If the nuclear radius of 27 AI is 3.6 fermi, the approximate nuclear radius of 64Cu in fermi is (A) 2.4 (B) 1.2 (C) 4.8 (D) 3.6

Tardigrade Admin · Accepted Answer

Nuclear radius, R =R0 A1 / 3 where R0 is a constant and A is the mass number ∴ (RA I/RC u)=((27)1 / 3/(64)1 / 3)=(3/4) or RC u=(4/3) × RA l=(4/3) × 3.6 fermi =4.8 fermi

Q. If the nuclear radius of $^{27} A I$ is $3.6$ fermi, the approximate nuclear radius of $^{64} C u$ in fermi is

2.4

1.2

4.8

3.6

Nuclear radius, $R = R_{0} A^{1/3}$
where $R_{0}$ is a constant and $A$ is the mass number
$∴ \frac{R _{A} I}{R _{C} u} = \frac{( 27 ) ^{1/3}}{( 64 ) ^{1/3}} = \frac{3}{4}$
or $R_{C u} = \frac{4}{3} \times R_{A l} = \frac{4}{3} \times 3.6$ fermi $= 4.8$ fermi

Q. If the nuclear radius of 27AI is 3.6 fermi, the approximate nuclear radius of 64Cu in fermi is

2.4

1.2

4.8

3.6

Nuclear radius, R=R0​A1/3 where R0​ is a constant and A is the mass number ∴RC​uRA​I​=(64)1/3(27)1/3​=43​ or RCu​=34​×RAl​=34​×3.6 fermi =4.8 fermi

Q. If the nuclear radius of $^{27} A I$ is $3.6$ fermi, the approximate nuclear radius of $^{64} C u$ in fermi is

Nuclear radius, $R = R_{0} A^{1/3}$
where $R_{0}$ is a constant and $A$ is the mass number
$∴ \frac{R _{A} I}{R _{C} u} = \frac{( 27 ) ^{1/3}}{( 64 ) ^{1/3}} = \frac{3}{4}$
or $R_{C u} = \frac{4}{3} \times R_{A l} = \frac{4}{3} \times 3.6$ fermi $= 4.8$ fermi