Question

If the median of following frequency distribution is $k,$ then $10k=$

C.I.	0 - 10	10 - 20	20 - 30	30 - 40	40 - 50	50 - 60
$f_1$	4	6	3	8	5	4

Answer 1

Answer: 325

We have,

Class Interval	Frequency	Cumulative frequency
$0-10$	$4$	$4$
$10-20$	$6$	$10$
$20-30$	$3$	$13$
$30-40$	$8$	$21$
$40-50$	$5$	$26$
$50-60$	$4$	$30$

Total, $N=30\Rightarrow \frac{N}{2}=15$
This value appears in the class $30-40$ . Therefore,
$L=30$ , $\text{CF}=21$ , $f=8$ , $h=10$
Median $=\ell +\frac{\frac{N}{2}-CF}{f}\times h$
$=30+\frac{15-13}{8}\times 10$
$k=30+\frac{20}{8}=32.5$