If the maximum concentration of PbCl 2 in water is 0.01 M at 25° C, its maximum concentration in 0.1 M NaCl will be

Question

If the maximum concentration of PbCl 2 in water is 0.01 M at 25° C, its maximum concentration in 0.1 M NaCl will be (A) 2 × 10-3 M (B) 1 × 10-4 M (C) 1.6 × 10-2 M (D) 4 × 10-4 M

Tardigrade Admin · Accepted Answer

undersetS PbCl 2 longrightarrow undersetS Pb 2++ underset2 S2 Cl - K sp =S(2 S)2=4 S3 =4 ×(10-2)3=4 × 10-6 In 0.1 M NaCl ,[ Cl -]=0.1+2 × 10-2 ≈ 0.1 M As 0.01 M PbCl 2 ≡ 0.02 M Cl - [ Pb 2+][ Cl -]2=K sp or [ Pb 2+](0.10)2=4 × 10-6 or [ Pb 2+]=4 × 10-4 M

Q. If the maximum concentration of $P b C l_{2}$ in water is $0.01 M$ at $2 5^{\circ} C$ , its maximum concentration in $0.1 M N a Cl$ will be

$2 \times 1 0^{- 3} M$

$1 \times 1 0^{- 4} M$

$1.6 \times 1 0^{- 2} M$

$4 \times 1 0^{- 4} M$

Q. If the maximum concentration of PbCl2​ in water is 0.01M at 25∘C, its maximum concentration in 0.1MNaCl will be

2×10−3M

1×10−4M

1.6×10−2M

4×10−4M

SPbCl2​​⟶SPb2+​+2S2Cl−​ Ksp​=S(2S)2=4S3 =4×(10−2)3=4×10−6 In 0.1MNaCl,[Cl−]=0.1+2×10−2≈0.1M As 0.01MPbCl2​≡0.02MCl− [Pb2+][Cl−]2=Ksp​ or [Pb2+](0.10)2=4×10−6 or [Pb2+]=4×10−4M

Q. If the maximum concentration of $P b C l_{2}$ in water is $0.01 M$ at $2 5^{\circ} C$ , its maximum concentration in $0.1 M N a Cl$ will be

$2 \times 1 0^{- 3} M$

$1 \times 1 0^{- 4} M$

$1.6 \times 1 0^{- 2} M$

$4 \times 1 0^{- 4} M$