If the mass of neutron =1.7× 10- 27 text kg , then the de-Broglie wavelength of neutron of energy text3 eV is (.h=6.6× (10)- 34 J-s.)

Question

If the mass of neutron =1.7× 10- 27 text kg , then the de-Broglie wavelength of neutron of energy text3 eV is (.h=6.6× (10)- 34 J-s.) (A) 1.6× 10- 16m (B) 1.6× 10- 11m (C) 1.4× 10- 10m (D) 1.4× 10- 11m

Tardigrade Admin · Accepted Answer

Given E=3 eV=3× 1.6× 10- 19 J We know that λ =(h/√2 m E) =(6.6 × 10- 34/√2 × 1.7 × 10- 27 × 3 × 1.6 × 10- 19)=1.65× 10- 11 m

Q. If the mass of neutron $= 1.7 \times 1 0^{- 27} kg$ , then the de-Broglie wavelength of neutron of energy $3 eV$ is $(h = 6.6 \times (10)^{- 34} J - s)$

$1.6 \times 1 0^{- 16} m$

$1.6 \times 1 0^{- 11} m$

$1.4 \times 1 0^{- 10} m$

$1.4 \times 1 0^{- 11} m$

Given $E = 3 e V = 3 \times 1.6 \times 1 0^{- 19}$ J
We know that $λ = \frac{h}{2 m E}$
$= \frac{6.6 \times 1 0 ^{- 34}}{2 \times 1.7 \times 1 0 ^{- 27} \times 3 \times 1.6 \times 1 0 ^{- 19}} = 1.65 \times 1 0^{- 11} m$

Q. If the mass of neutron =1.7×10−27 kg , then the de-Broglie wavelength of neutron of energy 3 eV is (h=6.6×(10)−34J−s)

1.6×10−16m

1.6×10−11m

1.4×10−10m

1.4×10−11m