If the magnetic field of a plane electromagnetic wave is given by (The speed of light = 3 × 108 /m/s) B = 100 × 10-6 sin [ 2 π × 2 × 1015 ( t - (x/c) ) ] then the maximum electric field associated with it is :

Question

If the magnetic field of a plane electromagnetic wave is given by (The speed of light = 3 × 108 /m/s) B = 100 × 10-6 sin [ 2 π × 2 × 1015 ( t - (x/c) ) ] then the maximum electric field associated with it is : (A)  4 × 104 N / C (B)  4.5 × 104 N / C (C)  6 × 104 N / C (D)  3 × 104 N / C

Tardigrade Admin · Accepted Answer

E0 = B0 × C = 100 × 10-6 × 3 × 108 = 3 × 104 N/C ∴ correct answer is 3 × 104 N/C

Q. If the magnetic field of a plane electromagnetic wave is given by (The speed of light = $3 \times 1 0^{8} / m / s$ )
$B = 100 \times 1 0^{- 6} sin [2 π \times 2 \times 1 0^{15} (t - \frac{x}{c})]$ then the maximum electric field associated with it is :

$4 \times 1 0^{4} N / C$

$4.5 \times 1 0^{4} N / C$

$6 \times 1 0^{4} N / C$

$3 \times 1 0^{4} N / C$

$E_{0} = B_{0} \times C$
$= 100 \times 1 0^{- 6} \times 3 \times 1 0^{8}$
$= 3 \times 1 0^{4} N / C$
$∴$ correct answer is $3 \times 1 0^{4} N / C$

Q. If the magnetic field of a plane electromagnetic wave is given by (The speed of light = 3×108/m/s) B=100×10−6sin[2π×2×1015(t−cx​)] then the maximum electric field associated with it is :

4×104N/C

4.5×104N/C

6×104N/C

3×104N/C