If the length of the second hand in a stop clock is 3 cm The angular velocity and linear velocity of the tip is

Question

If the length of the second hand in a stop clock is 3 cm The angular velocity and linear velocity of the tip is (A) 0.2047 rad / s ; 0.0314 m s -1 (B) 0.2547 rad / s ; 0.314 m s -1 (C) 0.1472 rad / s ; 0.06314 m s -1 (D) 0.1047 rad / s ; 0.00314 m s -1

Tardigrade Admin · Accepted Answer

Here, r=3 cm =3 × 10-2 m , T=60 s ∴ ω =(2 π/T)=(2 ×(22 / 7)/60)=0.1047 rad / s v=r ω=(3 × 10-2) × 0.1047 =0.00314 m s -1

Q. If the length of the second hand in a stop clock is 3 cm The angular velocity and linear velocity of the tip is

$0.2047 r a d / s; 0.0314 m s^{- 1}$

$0.2547 r a d / s; 0.314 m s^{- 1}$

$0.1472 r a d / s; 0.06314 m s^{- 1}$

$0.1047 r a d / s; 0.00314 m s^{- 1}$

Here, $r = 3 c m = 3 \times 1 0^{- 2} m, T = 60 s$
$∴ ω = \frac{2 π}{T} = \frac{2 \times ( 22/7 )}{60} = 0.1047 r a d / s$
$v = r ω = (3 \times 1 0^{- 2}) \times 0.1047$
$= 0.00314 m s^{- 1}$

Q. If the length of the second hand in a stop clock is 3 cm The angular velocity and linear velocity of the tip is

0.2047rad/s;0.0314ms−1

0.2547rad/s;0.314ms−1

0.1472rad/s;0.06314ms−1

0.1047rad/s;0.00314ms−1

Here, r=3cm=3×10−2m,T=60s ∴ω=T2π​=602×(22/7)​=0.1047rad/s v=rω=(3×10−2)×0.1047 =0.00314ms−1

$0.2047 r a d / s; 0.0314 m s^{- 1}$

$0.2547 r a d / s; 0.314 m s^{- 1}$

$0.1472 r a d / s; 0.06314 m s^{- 1}$

$0.1047 r a d / s; 0.00314 m s^{- 1}$

Here, $r = 3 c m = 3 \times 1 0^{- 2} m, T = 60 s$
$∴ ω = \frac{2 π}{T} = \frac{2 \times ( 22/7 )}{60} = 0.1047 r a d / s$
$v = r ω = (3 \times 1 0^{- 2}) \times 0.1047$
$= 0.00314 m s^{- 1}$