Question

If the length of rod $A$ is $\left(3.25\pm 0.01\right)cm$ and that of $B$ is $\left(4.19\pm 0.01\right)cm,$ then the rod $B$ is longer than rod $A$ by

• A. $\left(0.94\pm 0.00\right)cm$
• B. $\left(0.94\pm 0.01\right)cm$
• C. $\left(0.94\pm 0.02\right)cm$
• D. $\left(0.94\pm 0.005\right)cm$

Answer 1

Answer: (C)

Given, length of rod $A$ is
$L_A=3.25\pm 0.01$
Of B is $L_B=4.19\pm 0.01$
Then, the rod B is longer than rod A by a length
$\Delta l=L_B-L_A$
$\Delta l=\left(4.19\pm 0.01\right)-\left(3.25\pm 0.01\right)$
$\Delta l=\left(0.94\pm 0.02\right)\text{c}\text{m}$