Question

If the length of an open organ pipe is $33.3$ cm, then the frequency of fifth overtone $(v_5=333m/s)$

• A. $3000Hz$
• B. $1500Hz$
• C. $2500Hz$
• D. $1250Hz$

Answer 1

Answer: (A)

$f_0=\frac{V}{2l}$
$=\frac{333}{2\times 33.3\times 10^{-2}}=\frac{1000}{2}=500Hz$
frequency for 5 th overtone
$\varphi =6f_0$
$=6\times 500$
$=3000Hz$