If the kinetic energy of a satellite orbiting around the earth is doubled then

Question

If the kinetic energy of a satellite orbiting around the earth is doubled then (A) the satellite will escape into the space. (B) the satellite will fall down on the earth (C) radius of its orbit will be doubled (D) radius of its orbit will become half.

Tardigrade Admin · Accepted Answer

(1/2)mv12=2((1/2) m v02) v1=√2v0 this is the value of escape velocity, hence the satellite will escape out from gravitation of earth

Q. If the kinetic energy of a satellite orbiting around the earth is doubled then

the satellite will escape into the space.

the satellite will fall down on the earth

radius of its orbit will be doubled

radius of its orbit will become half.

$\frac{1}{2} m v_{1}^{2} = 2 (\frac{1}{2} m v_{0}^{2})$
$v_{1} = 2 v_{0}$
this is the value of escape velocity, hence the satellite will escape out from gravitation of earth

Q. If the kinetic energy of a satellite orbiting around the earth is doubled then

the satellite will escape into the space.

the satellite will fall down on the earth

radius of its orbit will be doubled

radius of its orbit will become half.

21​mv12​=2(21​mv02​) v1​=2​v0​ this is the value of escape velocity, hence the satellite will escape out from gravitation of earth

$\frac{1}{2} m v_{1}^{2} = 2 (\frac{1}{2} m v_{0}^{2})$
$v_{1} = 2 v_{0}$
this is the value of escape velocity, hence the satellite will escape out from gravitation of earth