Question

If the ionization potential for hydrogen atom is $13.6eV$ , then the ionization potential for $H{e}^{+}$ ion should be:

• A. 13.6 eV
• B. 6.8 eV
• C. 54.4 eV
• D. 72.2 eV

Answer 1

Answer: (C)

I.P for $H{e}^{+}$ion $=$I.P
for $H\times (Z{)}^2$
where, $Z$ = atomic number
$\therefore I.P.=13.6\times (2{)}^2$
$13.6\times 4=54.4eV$