Tardigrade
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Tardigrade
Question
Physics
If the heat of 110 J is added to a gaseous system, whose internal energy is 40 J , then the amount of external work done is:
Q. If the heat of
110
J
is added to a gaseous system, whose internal energy is
40
J
, then the amount of external work done is:
3238
267
J & K CET
J & K CET 2019
Thermodynamics
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A
180
J
6%
B
70
J
81%
C
110
J
9%
D
30
J
4%
Solution:
Heat added to the system
Δ
Q
=
110
J
Internal energy
Δ
U
=
40
J
External work done is given by
Δ
W
=
Δ
Q
−
Δ
U
=
110
−
40
=
70
J