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Q. If the heat of $ 110\,\,J $ is added to a gaseous system, whose internal energy is $ 40\,\,J $ , then the amount of external work done is:

J & K CETJ & K CET 2019Thermodynamics

Solution:

Heat added to the system $ \Delta Q=110 \,J $
Internal energy $ \Delta U=40\, J $
External work done is given by
$ \Delta W=\Delta Q-\Delta U=110-40 $
$= 70 \,J$