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Question
Mathematics
If the function f(x)=x3-6x2+ax+b satisfies all conditions of Rolle's theorem in x∈ [1,3], then the value of a is equal to
Q. If the function
f
(
x
)
=
x
3
−
6
x
2
+
a
x
+
b
satisfies all conditions of Rolle's theorem in
x
∈
[
1
,
3
]
,
then the value of
a
is equal to
2513
216
NTA Abhyas
NTA Abhyas 2020
Application of Derivatives
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A
1
B
11
C
22
D
2
Solution:
For Rolle’s theorem,
f
(
1
)
=
f
(
3
)
⇒
1
−
6
+
a
+
b
=
27
−
54
+
3
a
+
b
⇒
2
a
=
22
⇒
a
=
11