If the equivalent resistance between the terminal points P and Q is 4 Ω in the given circuit, then find out the resistance of R in ohms

Question

If the equivalent resistance between the terminal points P and Q is 4 Ω in the given circuit, then find out the resistance of R in ohms <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-mgjgldutf8el.png" /> (A) 7 (B) 4 (C) 2 (D) 5

Tardigrade Admin · Accepted Answer

Equivalent circuit is, <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-mgjgldutdqi8.png" /> Therefore equivalent resistance is, Re q=(R ((4 R/3))/R + (4 R)3) 4=(4 R/7) R=7 Ω

Q. If the equivalent resistance between the terminal points $P$ and $Q$ is $4 Ω$ in the given circuit, then find out the resistance of $R$ in ohms

$7$

$4$

$2$

$5$

Equivalent circuit is,

Therefore equivalent resistance is,
$R_{e q} = \frac{R ( \frac{4 R}{3} )}{R + \frac{4 R}{3}}$
$4 = \frac{4 R}{7}$
$R = 7 Ω$

Q. If the equivalent resistance between the terminal points P and Q is 4Ω in the given circuit, then find out the resistance of R in ohms

7

4

2

5

Equivalent circuit is, Therefore equivalent resistance is, Req​=R+34R​R(34R​)​ 4=74R​ R=7Ω

Q. If the equivalent resistance between the terminal points $P$ and $Q$ is $4 Ω$ in the given circuit, then find out the resistance of $R$ in ohms

$7$

$4$

$2$

$5$

Equivalent circuit is,

Therefore equivalent resistance is,
$R_{e q} = \frac{R ( \frac{4 R}{3} )}{R + \frac{4 R}{3}}$
$4 = \frac{4 R}{7}$
$R = 7 Ω$