Question

If the equation of hyperbola is $\frac{x^2}{9}-\frac{y^2}{16}=1$, then

• A. transverse axis is along $x$ -axis of length 6
• B. transverse axis is along $y$ -axis of length 8
• C. conjugate axis is along $y$ -axis of length 6
• D. None of the above

Answer 1

Answer: (A)

The foci are always on the transverse axis. It is the positive term whose denominator gives the transverse axis.
Thus, $\frac{x^2}{9}-\frac{y^2}{16}=1$ has transverse axis along $x$ -axis of length $6$ .