If the energy of the photon is increased by a factor of 4 , then its momentum

Question

If the energy of the photon is increased by a factor of 4 , then its momentum (A) Does not change (B) Decreases by a factor of 4 (C) Increases by a factor of 4 (D) Decreases by a factor of 2

Tardigrade Admin · Accepted Answer

P=(h/λ), E=(h c/λ) ⇒ E=P c.

Q. If the energy of the photon is increased by a factor of 4 , then its momentum

Does not change

Decreases by a factor of 4

Increases by a factor of 4

Decreases by a factor of 2

$P = \frac{h}{λ}, E = \frac{h c}{λ}$
$\Rightarrow E = P c .$

Q. If the energy of the photon is increased by a factor of 4 , then its momentum

Does not change

Decreases by a factor of 4

Increases by a factor of 4

Decreases by a factor of 2

P=λh​,E=λhc​ ⇒E=Pc.

$P = \frac{h}{λ}, E = \frac{h c}{λ}$
$\Rightarrow E = P c .$