If the energy of a photon of sodium light (λ = 589 nm) equals the band gap of semiconductor, the minimum energy required to create hole electron pair

Question

If the energy of a photon of sodium light (λ = 589 nm) equals the band gap of semiconductor, the minimum energy required to create hole electron pair (A) 1.1 eV (B) 2.1 eV (C) 3.2 eV (D) 1.5 eV

Tardigrade Admin · Accepted Answer

Using, E = Eg = (hc/λ) = (6.6×10-34× 3× 108/589× 10-9) J = ( 6.6×10-34 × 3× 108/589× 10-9× 1.6× 10-19) eV =2.1 eV

Q. If the energy of a photon of sodium light $(λ = 589 nm)$ equals the band gap of semiconductor, the minimum energy required to create hole electron pair

$1.1 e V$

$2.1 e V$

$3.2 e V$

$1.5 e V$

Using, $E = E_{g} = \frac{h c}{λ}$
$= \frac{6.6 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{589 \times 1 0 ^{- 9}} J$
$= \frac{6.6 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{589 \times 1 0 ^{- 9} \times 1.6 \times 1 0 ^{- 19}} e V$
$= 2.1 e V$

Q. If the energy of a photon of sodium light (λ=589nm) equals the band gap of semiconductor, the minimum energy required to create hole electron pair

1.1eV

2.1eV

3.2eV

1.5eV