Question

If the end correction of an open pipe is $0.8cm$ then the inner radius of that pipe will be

• A. $\frac{1}{3}cm$
• B. $\frac{2}{3}cm$
• C. $\frac{3}{2}cm$
• D. $0.2cm$

Answer 1

Answer: (B)

For open organ pipe
$\Delta L=1.2\times r$
$\therefore r=\Delta L\times \frac{1}{1.2}=\frac{0.8}{1.2}=\frac{2}{3}cm.$