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  4. If the end correction of an open pipe is 0.8 cm then the inner radius of that pipe will be

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Q. If the end correction of an open pipe is $0.8 \, cm$ then the inner radius of that pipe will be

NTA AbhyasNTA Abhyas 2022

Solution:

For open organ pipe
$\Delta L=1.2\times r$
$\therefore r=\Delta L\times \frac{1}{1.2}=\frac{0.8}{1.2}=\frac{2}{3} \, cm.$