If the elevation in boiling point of a solution of 10 g of solute (mol. wt. =100) in 100 g of water is Δ Tb, the ebullioscopic constant of water is

Question

If the elevation in boiling point of a solution of 10 g of solute (mol. wt. =100) in 100 g of water is Δ Tb, the ebullioscopic constant of water is (A) 10 (B) 100 Tb (C) Δ Tb (D)  (Δ Tb/10)

Tardigrade Admin · Accepted Answer

We know that, Δ Tb = (1000 × Kb× W/W× M) M = (1000× Kb × W/W × Δ Tb) Δ Tb = (1000 × Kb× 10/100× 100) Δ Tb = Kb

Q. If the elevation in boiling point of a solution of $10 g$ of solute $(m o l$ . wt. $= 100$ ) in $100 g$ of water is $Δ T_{b}$ , the ebullioscopic constant of water is

$10$

$100 T_{b}$

$Δ T_{b}$

$\frac{Δ T _{b}}{10}$

We know that, $Δ T_{b} = \frac{1000 \times K _{b} \times W}{W \times M}$
$M = \frac{1000 \times K _{b} \times W}{W \times Δ T _{b}}$
$Δ T_{b} = \frac{1000 \times K _{b} \times 10}{100 \times 100}$
$Δ T_{b} = K_{b}$

Q. If the elevation in boiling point of a solution of 10g of solute (mol. wt. =100) in 100g of water is ΔTb​, the ebullioscopic constant of water is

10

100Tb​

ΔTb​

10ΔTb​​