Question

If the electronegativity difference between two atoms $A$ and $B$ is $2.0$, then the percentage of covalent character in the molecule is

• A. 54%
• B. 46%
• C. 23%
• D. 72%

Answer 1

Answer: (B)

According to Hannay and Smith equation
$\therefore \%$ ionic character
$=16\left(x_A-x_B\right)+3.5{\left(x_A-x_B\right)}^2$
where, $x_A$ and $x_B$ are the electronegativites of the atoms $A$ and $B$ respectively.
$\therefore \%$ ionic character $=16(2)+3.5(2{)}^2$
$=32+14=46\%$