Question

If the electronegativity difference between two atoms A and B is 2.0, then the percentage of co-valent character in the molecule is

• A. 54%
• B. 46%
• C. 23%
• D. 72%

Answer 1

Answer: (B)

According to Hannay and Smith equation $\therefore$ % ionic character $=16(x_A-x_B)+3.5{(x_A-x_B)}^2$ where, $x_A$ and $x_B$ are the electronegativitys of the atoms A and B respectively. $\therefore$ % ionic character $=16(2)+3.5{(2)}^2$ $=32+14=46$ c