If the electric flux entering and leaving an enclosed surface respectively is φ1 and φ2, the electric charge inside the surface will be

Question

If the electric flux entering and leaving an enclosed surface respectively is φ1 and φ2, the electric charge inside the surface will be (A) (φ2-φ1)ε0 (B) ((φ2+φ1)/ε0) (C) ((φ2-φ1)/ε0) (D) (φ2+φ1)ε0

Tardigrade Admin · Accepted Answer

According to Gaussâs theorem, charge in flux (charge enclosed by the surface/ε0) ∴ q=(φ2-φ1)ε0.

Q. If the electric flux entering and leaving an enclosed surface respectively is $ϕ_{1}$ and $ϕ_{2}$ , the electric charge inside the surface will be

$(ϕ_{2} - ϕ_{1}) ε_{0}$

$\frac{( ϕ _{2} + ϕ _{1} )}{ε _{0}}$

$\frac{( ϕ _{2} - ϕ _{1} )}{ε _{0}}$

$(ϕ_{2} + ϕ_{1}) ε_{0}$

According to Gauss’s theorem, charge in flux $\frac{c ha r g e e n c l ose d b y t h e s u r f a ce}{ε _{0}}$
$∴ q = (ϕ_{2} - ϕ_{1}) ε_{0}$ .

Q. If the electric flux entering and leaving an enclosed surface respectively is ϕ1​ and ϕ2​, the electric charge inside the surface will be

(ϕ2​−ϕ1​)ε0​

ε0​(ϕ2​+ϕ1​)​

ε0​(ϕ2​−ϕ1​)​

(ϕ2​+ϕ1​)ε0​