If the distance between two consecutive base pairs is 0.34nm and the total number of base pairs of a DNA double helix in a typical mammalian cell is 6.6 × 109 bp, then the length of the DNA is approximately:

Question

If the distance between two consecutive base pairs is 0.34nm and the total number of base pairs of a DNA double helix in a typical mammalian cell is 6.6 × 109 bp, then the length of the DNA is approximately: (A) 2.0 meters (B) 2.5 meters (C) 2.2 meters (D) 2.7 meters

Tardigrade Admin · Accepted Answer

Length of DNA = Number of base pairs × 0.34 nm = 6.6 × 109 × 0.34 nm = 6.6 × 109 × 0.34 × 10-9 m = 2.2 m

Q. If the distance between two consecutive base pairs is 0.34nm and the total number of base pairs of a DNA double helix in a typical mammalian cell is $6.6 \times 1 0^{9}$ bp, then the length of the DNA is approximately:

2.0 meters

2.5 meters

2.2 meters

2.7 meters

Length of DNA = Number of base pairs $\times 0.34 nm$
$= 6.6 \times 1 0^{9} \times 0.34 nm$
$= 6.6 \times 1 0^{9} \times 0.34 \times 1 0^{- 9} m$
$= 2.2 m$

Q. If the distance between two consecutive base pairs is 0.34nm and the total number of base pairs of a DNA double helix in a typical mammalian cell is 6.6×109 bp, then the length of the DNA is approximately: