If the dipole of moment 2.57 × 10-17 cm is placed into an electric field of magnitude 3.0 × 104 N / C such that the fields lines are aligned at 30° with the line joining P to the dipole, what torque acts on the dipole?

Question

If the dipole of moment 2.57 × 10-17 cm is placed into an electric field of magnitude 3.0 × 104 N / C such that the fields lines are aligned at 30° with the line joining P to the dipole, what torque acts on the dipole? (A) 7.7 × 10-13 Nm (B) 3.855 × 10-13 Nm (C) 3.855 × 10-15 Nm (D) 7.7 × 10-15 Nm

Tardigrade Admin · Accepted Answer

τ =(2.57 × 10-17 Cm )(3.0 × 104 ( N / C ))((1/2)) =3.855 × 10-13 Nm

Q. If the dipole of moment $2.57 \times 1 0^{- 17} c m$ is placed into an electric field of magnitude $3.0 \times 1 0^{4} N / C$ such that the fields lines are aligned at $3 0^{\circ}$ with the line joining $P$ to the dipole, what torque acts on the dipole?

$7.7 \times 1 0^{- 13} N m$

$3.855 \times 1 0^{- 13} N m$

$3.855 \times 1 0^{- 15} N m$

$7.7 \times 1 0^{- 15} N m$

$τ = (2.57 \times 1 0^{- 17} C m) (3.0 \times 1 0^{4} \frac{N}{C}) (\frac{1}{2})$
$= 3.855 \times 1 0^{- 13} N m$

Q. If the dipole of moment 2.57×10−17cm is placed into an electric field of magnitude 3.0×104N/C such that the fields lines are aligned at 30∘ with the line joining P to the dipole, what torque acts on the dipole?

7.7×10−13Nm

3.855×10−13Nm

3.855×10−15Nm

7.7×10−15Nm