If the de-Broglie wavelength of the fourth Bohr orbit of hydrogen atom is 4 overset texto mathop textA , the circumference of the orbit will be

Question

If the de-Broglie wavelength of the fourth Bohr orbit of hydrogen atom is 4 overset texto mathop textA , the circumference of the orbit will be (A)  4 overset texto mathop textA  (B)  4 nm  (C)  16 overset texto mathop textA  (D)  16 nm

Tardigrade Admin · Accepted Answer

According to Bohrs postulate and de-Broglie equation 2π r=nλ Here, 2π r= circumference of the orbit n=4 λ =4 overset texto mathop textA ∴ 2π r=4× 4 =16 overset texto mathop textA

Q. If the de-Broglie wavelength of the fourth Bohr orbit of hydrogen atom is $4 A o$ , the circumference of the orbit will be

$4 A o$

$4 nm$

$16 A o$

$16 nm$

According to Bohrs postulate and de-Broglie equation $2 π r = nλ$ Here, $2 π r =$ circumference of the orbit $n = 4$ $λ = 4 A o$ $∴$ $2 π r = 4 \times 4$ $= 16 A o$

Q. If the de-Broglie wavelength of the fourth Bohr orbit of hydrogen atom is 4Ao , the circumference of the orbit will be

4Ao

4nm

16Ao

16nm