If the conjugate of ⇒ be x1-y1=-7 ,then

Question

If the conjugate of ⇒ be x1-y1=-7 ,then (A)  PQ=(-3-y1/4-x1)  (B)  y=x  (C)  ∵  (D)  PQ

Tardigrade Admin · Accepted Answer

Given, conjugate of text10-3 . 1μ V text1. text96× text10- text8 text m/ texts text2. text12× text10 text8 text m/ texts text3. text18× text108m/s text3. text33× 10 text8 text m/ texts θ = text45° (1/3)ML2

Q. If the conjugate of $\Rightarrow$ be $x_{1} - y_{1} = - 7$ ,then

$PQ = \frac{- 3 - y _{1}}{4 - x _{1}}$

$y = x$

$∵$

$PQ$

Given, conjugate of $1 0^{- 3}$ . $1 μ V$ $1.96 \times 1 0^{- 8} m / s$ $2.12 \times 1 0^{8} m / s$ $3.18 \times 1 0^{8} m / s$ $3.33 \times 10^{8} m / s$ $θ = 45^{\circ}$ $\frac{1}{3} M L^{2}$

Q. If the conjugate of ⇒ be x1​−y1​=−7 ,then

PQ=4−x1​−3−y1​​

y=x

∵

PQ

Given, conjugate of 10−3 . 1μV 1.96×10−8 m/s 2.12×108 m/s 3.18×108m/s 3.33×108 m/s θ=45∘ 31​ML2

Q. If the conjugate of $\Rightarrow$ be $x_{1} - y_{1} = - 7$ ,then

$PQ = \frac{- 3 - y _{1}}{4 - x _{1}}$

$y = x$

$∵$

$PQ$

Given, conjugate of $1 0^{- 3}$ . $1 μ V$ $1.96 \times 1 0^{- 8} m / s$ $2.12 \times 1 0^{8} m / s$ $3.18 \times 1 0^{8} m / s$ $3.33 \times 10^{8} m / s$ $θ = 45^{\circ}$ $\frac{1}{3} M L^{2}$