If the concentration of CrO 42- ions in a saturated solution of silver chromate is 2 × 10-4 M, the solubility product of silver chromate would be

Question

If the concentration of CrO 42- ions in a saturated solution of silver chromate is 2 × 10-4 M, the solubility product of silver chromate would be (A)  32× 10-12 (B)  8× 10-12 (C)  16× 10-12 (D)  8× 10-8

Tardigrade Admin · Accepted Answer

Ag 2 undersetsCrO 4(s) leftharpoons underset2s2 Ag ++ undersetsCrO 42- Given, [ CrO 42-] =s= × 10-4 ∴ [ Ag +] =2 s=2 × 2 × 10-4 =4 × 10-4 K sp =[ Ag +]2[ CrO 42-] =[4 × 10-4]2[2 × 10-4] =32 × 10-12

Q. If the concentration of $C r O_{4}^{2 -}$ ions in a saturated solution of silver chromate is $2 \times 1 0^{- 4} M$ , the solubility product of silver chromate would be

$32 \times 1 0^{- 12}$

$8 \times 1 0^{- 12}$

$16 \times 1 0^{- 12}$

$8 \times 1 0^{- 8}$

Q. If the concentration of CrO42−​ ions in a saturated solution of silver chromate is 2×10−4M, the solubility product of silver chromate would be

32×10−12

8×10−12

16×10−12

8×10−8

Ag2​sCrO4​​(s)⇌2s2Ag+​+sCrO42−​​ Given, [CrO42−​]=s=×10−4 ∴[Ag+]=2s=2×2×10−4 =4×10−4 Ksp​=[Ag+]2[CrO42−​] =[4×10−4]2[2×10−4] =32×10−12

Q. If the concentration of $C r O_{4}^{2 -}$ ions in a saturated solution of silver chromate is $2 \times 1 0^{- 4} M$ , the solubility product of silver chromate would be

$32 \times 1 0^{- 12}$

$8 \times 1 0^{- 12}$

$16 \times 1 0^{- 12}$

$8 \times 1 0^{- 8}$