If the concentration is expressed in mole per litre, the unit of rate constant for a first order reaction is:

Question

If the concentration is expressed in mole per litre, the unit of rate constant for a first order reaction is: (A)  textmol L-1 (B) L textmol -1 (C)  s-1  (D)  textmol L-1 s-1

Tardigrade Admin · Accepted Answer

For first order reaction: Rate =(d x/d t) k[A] k=( text mol L-1 s-1/ text mol L-1)=s-1 Hence, for first order reaction unit of rate constant is sec -1.

Q. If the concentration is expressed in mole per litre, the unit of rate constant for a first order reaction is:

$mol L^{- 1}$

$L mol^{- 1}$

$s^{- 1}$

$mol L^{- 1} s^{- 1}$

For first order reaction:
Rate $= \frac{d x}{d t} k [A]$
$k = \frac{mol L ^{- 1} s ^{- 1}}{mol L ^{- 1}} = s^{- 1}$
Hence, for first order reaction unit of rate constant is $sec^{- 1}$ .

Q. If the concentration is expressed in mole per litre, the unit of rate constant for a first order reaction is:

molL−1

Lmol−1

s−1

molL−1s−1

For first order reaction: Rate =dtdx​k[A] k= mol L−1 mol L−1s−1​=s−1 Hence, for first order reaction unit of rate constant is sec−1.

$mol L^{- 1}$

$L mol^{- 1}$

$s^{- 1}$

$mol L^{- 1} s^{- 1}$

For first order reaction:
Rate $= \frac{d x}{d t} k [A]$
$k = \frac{mol L ^{- 1} s ^{- 1}}{mol L ^{- 1}} = s^{- 1}$
Hence, for first order reaction unit of rate constant is $sec^{- 1}$ .