Q.
If the complex numbers z1,z2 and z3 represent the vertices of an equilateral triangle such that ∣z1∣=∣z2∣=∣z3∣, then
1083
155
Complex Numbers and Quadratic Equations
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Solution:
Let ∣z1∣=∣z2∣=∣z3∣=k (say), ⇒z1,z2,z3 lie on a circle with centre at the origin and radius k.
As z1,z2,z3 are vertices of an equilateral triangle, the circumcentre and the centroid of the triangle coincide. Therefore, 31(z1+z2+z3)=0⇒z1+z2+z3=0