Q.
If the coefficients of the three successive terms in the binomial expansion of (1+x)n are in the ratio 1:7:42, then the first of these terms in the expansion is :
Let T2−1,Tr,Tr+1 be the three successive terms of (1+x)n ⇒nCr:nCr−1:nCr=1:7:42 ⇒nCr−2nCr−1=7;nCr−1nCr=742=6⇒r−1n−r+2=7;rn−r+1=6 ⇒r=8,n=55 ⇒Tr−1=T7 ⇒ First of the three given terms will be 7th