Question

If the average of the numbers $1$, $2$, $3$, $...$, $98$, $99$, $x$ is $100x$, then the value of $x$ is

• A. $\frac{51}{100}$
• B. $\frac{50}{99}$
• C. $\frac{50}{101}$
• D. $\frac{51}{59}$

Answer 1

Answer: (C)

$\frac{1+2+3+...+99+x}{100}=100x$
$\Rightarrow 10000x=\frac{99\cdot 100}{2}+x$
$\Rightarrow x=\frac{50}{101}$