We know that the acute angle θ between two lines with slopes m1 and m2 is given by tanθ=∣∣1+m1m2m2−m1∣∣…(i)
Let m1=21, m2=m and θ=4π.
Now, putting these values in (i), we get tan4π=∣∣1+21mm−21∣∣ ⇒1=∣∣2+m2m−1∣∣,
wihich gives 2+m2m−1=1 or 2+m2m−1=−1
Therefore m=3 or m=−31
Hence, slope of the other line is 3 or −31.