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Tardigrade
Question
Chemistry
If the activation energy for the forward reaction is 250 kJ mol-1 and that of the reverse reaction is 360 kJ mol-1, what is the enthalpy change for the reaction?
Q. If the activation energy for the forward reaction is
250
k
J
m
o
l
−
1
and that of the reverse reaction is
360
k
J
m
o
l
−
1
,
what is the enthalpy change for the reaction?
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VMMC Medical
VMMC Medical 2013
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A
+
110
k
m
o
l
−
1
B
−
110
k
J
m
o
l
−
1
C
+
610
k
J
m
o
l
−
1
D
−
610
k
J
m
o
l
−
1
Solution:
Δ
H
=
E
f
−
E
b
=
250
−
360
k
J
=
110
k
J
.
