1. Tardigrade
  2. Question
  3. Chemistry
  4. If the activation energy for the forward reaction is 250 kJ mol-1 and that of the reverse reaction is 360 kJ mol-1, what is the enthalpy change for the reaction?

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Q. If the activation energy for the forward reaction is $ 250\,kJ\,mo{{l}^{-1}} $ and that of the reverse reaction is $ 360\,kJ\,mo{{l}^{-1}}, $ what is the enthalpy change for the reaction?

VMMC MedicalVMMC Medical 2013

Solution:

$ \Delta H={{E}_{f}}-{{E}_{b}}=250-360\,kJ=110\,kJ. $

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